X^2+1.6x=-0.04

Solution for X^2+1.6x=-0.04 equation:

X^2+1.6X=-0.04

We move all terms to the left:

X^2+1.6X-(-0.04)=0

We add all the numbers together, and all the variables

X^2+1.6X+0.04=0

a = 1; b = 1.6; c = +0.04;
Δ = b2-4ac
Δ = 1.62-4·1·0.04
Δ = 2.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{2.4}}{2*1}=\frac{-1.6-\sqrt{2.4}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{2.4}}{2*1}=\frac{-1.6+\sqrt{2.4}}{2}
$